$1-x\cdot4\left(3-5x+2y\right)$
$5x^2-8x+13$
$\frac{3\:x\:3\:+3\:x\:2\:-8\:x-1\:0}{x+1}$
$\frac{1-tan^4x}{\sec^2x}=1-\tan^2x$
$-683-593$
$2pq\:+\:3p\:+\:12q\:-\:15q\:+\:7pq\:-\:13p$
$\lim_{x\to+\infty}\left(1-\frac{4}{x}\right)^{6x}$
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