$2a^2b-\frac{3}{2}a^2b-1$

$\lim_{x\to0}\left(-\frac{sin^2\left(x\right)}{cos\left(x\right)-1}\right)$

$\frac{64n^1-m^1}{4n-m}$

$\frac{3x^3+2x^2-8}{x\:-4}$

$3x+\:2<-4$

$\log_{16}\left(\frac{1}{2}x\right)+\log_{16}\left(\frac{1}{2}\right)=\log_{16}\left(6\right)$

$5m^2-4m^2+20m^2$