$\int ln\left(8x+4\right)dx$
$m^2+m+25$
$\lim_{x\to\infty}x\tan\left(\frac{1}{x^2}\right)$
$\lim_{x\to\infty}\frac{x\sin\left(2x\right)}{x^2+1}$
$sec\left(45\right)+sen\left(45\right)$
$\left(-5\right)-\left(-20\right)$
$-5\cdot13$
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