$-2,53+3,1$
$10\sin\left(x\right)^2=3\cos\left(x\right)^2$
$1-3-4+4$
$\int\frac{x^4-2x^2+3x+4}{x^4-x^2-2x+2}dx$
$\left(6a-6b^3\right)^2$
$\left(3x+2y\right)dx+2xdy=0$
$\frac{2x+4}{6}\ge\frac{x}{6}-3$
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