$\left(x\:+\:y\right)\:-\:1\:\left(x\:+\:y\:\right)\:+\:1$
$12+4x=-4x-12$
$16x^2+40+25$
$3t+7t^2-t$
$2x-12<x+2$
$\:\left(2x\:+\:25\right)\:\left(\:2x\:-25\right)$
$3u^2-90u+111=0$
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