$a^2-6a+1$
$\int12jkg^{-1}dg$
$t^2\:+\:20t\:+\:20$
$2x^3y^{-3}\cdot2x^{-1}y^3$
$13x+3y-4z=21$
$\frac{\left(\tan\:323-\tan\:8\right)}{\left(1+\tan\:323\tan\:8\right)}=-1$
$121-x^6$
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