$$4-3x>4$$

$$\lim_{x\to\infty}\left(\left(x^3\right)\cdot5^{-x}\right)$$

$$\left(3.4x+5\right)\:\left(3.5x-2\right)$$

$$\frac{\left(\csc\left(x\right)-\cot\left(x\right)\right)\left(\csc\left(x\right)+\cot\left(x\right)\right)}{\sec\left(x\right)}=\cos\left(x\right)$$

$$7-19+15-8+6-13-6$$

$$5a^2-10a$$

$$4x-5y=20$$