$x^2+6<7x$
$\left(x^2+5\right)\frac{dy}{dx}=-2x\left(y+1\right)$
$\:\frac{1}{5-x}\frac{1}{-\left(5-x\right)}$
$\lim_{x\to0}\left(\frac{x^5}{\sin\left(2x\right)-2x+4x^2}\right)$
$\left(x-12\right)\left(x-3\right)$
$\frac{3x^5-x}{x}$
$x\:+\:4+7$
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