$3x^2-8x-4$
$\frac{dy}{dx}=4xy-2x,y\left(0\right)=10$
$-y^2=y-2$
$10-\left(-8-\left(15-13\right)\right)$
$( \frac { 1 } { 2 } x - 2 ) ^ { 2 }$
$\left(3x^2+10x+9\right)+\left(-2x^4+10x^3-x-2\right)$
$\frac{dy}{dt}=23$
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