$\int\left(2x^5\right)dx$
$y^{-4}\:y^2$
$\frac{v}{4}+1$
$\left(\frac{14\left(x^2\right)^3\left(x^3\right)^2}{\left(x^3\right)^4}\right)$
$7-\left(-17\right)^2$
$8x^3+64$
$\left(2x^3+7\right)^2$
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