$42\cdot1$
$r^2\:+\:13r\:+\:30$
$671+-245$
$11+5q=14+4q$
$6x-3<3x+6$
$\left(7-x\right)^2$
$\frac{\left(2x^2-11x+20\right)}{2x+3}$
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