$\left(\frac{4x+6}{\sqrt{x^2+3x+4}}\right)$
$\frac{1}{\sqrt{tan^2x+1}}$
$\left(x^{2a+2}-3x^{a-2}\right)^2$
$\lim_{x\to0}\frac{-2\tan\left(x\right)}{x}$
$9x^2-24x-16$
$x^2\frac{dy}{dx}=y^2-xy^2$
$\frac{j^4-625}{j-5}$
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