$\int\left(\frac{4}{x^3}\right)dx$
$1=sec^4x-tan^4x$
$1+2\sin\left(x\right)=3$
$\frac{x^3+y^3}{\sqrt[5]{x^3+1}+2x-1}$
$\left(-x^4+25^2\right)$
$3xy+y^2$
$\left(-4x+y\right)^2$
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