$ln\left(x+3\right)-ln\left(x\right)-5=0$
$0,23+-0,2$
$5x+2x^2=24$
$\lim_{x,y\to0}\left(\frac{x^2+y^2}{\sqrt{x^2+y^2+1}}\right)$
$\lim_{x\to-4}\left(x+4\:\:x^2-16\right)$
$e^4=x+3$
$8x-5\le7x+14$
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