$3\cdot\frac{\frac{2+\frac{2-x}{3}}{3}}{2}=1$
$\left(3y+4\right)+\left(6y+1\right)$
$\frac{-24x^2y}{8xy}$
$3-\left(-12-15+23\right)-\left(24-11\right)$
$\left(\cot^2\:x\:+1\right)\left(1-\cos^{2\:}x\right)=1$
$\frac{\left(x-4\right)^3-8}{x-6}$
$\frac{d}{dx}y^2=x^3$
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