$\sqrt{x^3\cdot x}$
$16q^2+48+36$
$2.x\frac{dy}{dx}-3.y=4.x^2$
$\left(4y\:+\:9x\right)\:\left(4y\:-\:9x\right)$
$1x^2+7x+14$
$4x^2=21$
$y'+3xe^y=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!