$y+\frac{1}{x}y=\sqrt{x}$
$\frac{d^2}{dx^2}\:\left(\frac{4x-1}{5x+3}\right)$
$\frac{\cot\left(x\right)}{\csc\left(x\right)-1}+\frac{\cot\left(x\right)}{\csc\left(x\right)+1}$
$xy'-y=2x^2$
$\int t^3\sqrt{9-t^2}dt$
$\left(4a+\:3b\right)\:^4$
$-8.50+10-9+15.50-5.50$
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