$\frac{dy}{dx}=\frac{6y}{x}$
$2x^2-3x-27$
$\frac{4x^3+6x^2-10x+8}{x-4}$
$17\:-\:\left(-\:4\right)\:.\:5\:+\:18\::\:\left(-\:9\right)\:-\:18\:$
$\frac{d}{dx}\ln\left(\frac{\left(x^2+5\right)^5}{\sqrt{6-x}}\right)$
$\left(g-3\right)\cdot6$
$2x+5>4$
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