$f\left(x\right)=\left(x-4\right)\left(3x+1\right)$

$\left(2x+4z\right)^2$

$\frac{5^{\frac{1}{2}}\cdot\:6^{\frac{1}{2}}}{12x^{\frac{1}{2}}}=\frac{\sqrt{5}\sqrt{6}\sqrt{x}}{12x}$

$\int3f^2df$

$-3x^4-6x^3+9x^2+3x$

$-\frac{1}{6}x=-5$

$\left(x+2\right)\left(x+2\right)\left(x-3\right)$