$-8+2x+x+22$
$t\:\frac{dx}{dt}+x=x^2$
$\left(x-5\right)\left(x+5\right)-\left(x+2\right)\left(x+8\right)$
$x^2\:+\:26x\:+\:169$
$\int6\left(6x-5\right)^4dx$
$\left(8x+9\right)+\left(8x-9\right)$
$2x-3-4\left(x^2-1\right)\ge10+x-4x^2$
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