x2(x+2)3(x−1)4(x2+1)\frac{x^2\left(x+2\right)^3}{\left(x-1\right)^4\left(x^2+1\right)}(x−1)4(x2+1)x2(x+2)3
(f6−52)2(f6−52)\left(\frac{f}{6}-\frac{5}{2}\right)^2\left(\frac{f}{6}-\frac{5}{2}\right)(6f−25)2(6f−25)
∫0∞27(4x23)dx\int_0^{\infty27}\left(\frac{4}{x^{\frac{2}{3}}}\right)dx∫0∞27(x324)dx
∫−2x−2x2−4x+3dx\int\frac{-2x-2}{x^2-4x+3}dx∫x2−4x+3−2x−2dx
2(x2−5)≥x(x−3)2\left(x^2-5\right)\ge x\left(x-3\right)2(x2−5)≥x(x−3)
x2−62+9x^2-6^2+9x2−62+9
(2)(2−c)>−4\frac{\left(2\right)}{\left(2-c\right)}>-4(2−c)(2)>−4
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