$\left(6-h\right)^{2}$
$\sin\left(x\right)\cos\left(x\right)=\cos\left(x\right)\cos\left(x\right)$
$\lim_{x\to1}\frac{4^x-3^x-1}{x^2-1}$
$\left(0.25-x\right)^{-1.5}$
$\frac{\left(-1\right)^n\cdot x^n}{3^n\sqrt{n}}$
$\left(9+3x\right)\left(-3+3x\right)$
$187.950+389.000$
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