$\left(120\right)\frac{m^{2}-25}{m-5}$
$\left(2a+3\right)\left(2b+z+4y\right)$
$\frac{x^7+2x^3-4x+5}{x-2}$
$8x^2-3=-10x$
$\:\left(x+4\right)\left(x-2\right)$
$\log\left(5\right)=2-\log\left(x+4\right)$
$-18\:x\:-10\:x\:9$
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