x3−64x+5\frac{x^3-64}{x+5}x+5x3−64
limx→infinito (−1xln2x)\lim_{x\to infinito\:}\left(\frac{-1}{xln^2x}\right)x→infinitolim(xln2x−1)
x2−411−2x\frac{x^2-4}{11-2x}11−2xx2−4
(3ag2+a)3\left(3ag^2+a\right)^3(3ag2+a)3
∫(x−4)sen(4−x)dx\int\left(x-4\right)sen\left(4-x\right)dx∫(x−4)sen(4−x)dx
∫(9−x)22dx\int\frac{\left(9-x\right)^2}{2}dx∫2(9−x)2dx
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