Applying the property of exponents, $\displaystyle a^{-n}=\frac{1}{a^n}$, where $n$ is a number
Evaluate the limit $\lim_{x\to{- \infty }}\left(\frac{1}{xe^x}\right)$ by replacing all occurrences of $x$ by $- \infty $
Apply the formula: $n^{- \infty }$$=0$, where $n=e$
An expression divided by zero tends to infinity
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