8xy;x=3;y=−28xy;x=3;y=-28xy;x=3;y=−2
−6(32)-6\left(32\right)−6(32)
(2x+5)2−(x−1)2\left(2x+5\right)^2-\left(x-1\right)^2(2x+5)2−(x−1)2
4x+87(x−8)(x+9)\frac{4x+87}{\left(x-8\right)\left(x+9\right)}(x−8)(x+9)4x+87
∫01xe−xdx\int_0^1xe^{-x}dx∫01xe−xdx
−8x+3≥27-8x+3\ge27−8x+3≥27
3cos2(x)+sin2(x)+5sin(x)=03\cos^2\left(x\right)+\sin^2\left(x\right)+5\sin\left(x\right)=03cos2(x)+sin2(x)+5sin(x)=0
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