$\frac{dx}{dy}=-\frac{1}{3}x^3$
$20x^2+44xy-48y^2$
$\lim_{x\to0}\left(\frac{x-\tan\left(x\right)}{x^3}\right)$
$\frac{\left(x^2+2x+1\right)}{4x^2+1}$
$x+1\:-\:x+3$
$x ^ { \frac { x } { x } }$
$8\left(6t-2v+5\right)$
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