$\left(v+1\right)^2$
$\frac{3x^2-2x-1}{x+1}$
$-6\left\{5-4\cdot2-\left[6+8-4\left(4\cdot5+3\right)-9\cdot2\right]+16\right\}-1$
$\left(2a+5\right)\left(3+b\right)$
$\left(3\right)\left(x\right)\left(-8y^3\right)$
$3+4-5+7$
$\left(3x-y\right)^3$
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