x+1+x−3+8x+1+x-3+8x+1+x−3+8
2 . 52\sqrt{2}\:.\:5\sqrt{2}2.52
62[yu]6^2\left[yu\right]62[yu]
2sinx2(1−cos2x)=1sin(x)\frac{2\sin x}{2\left(1-\cos2x\right)}=\frac{1}{\sin\left(x\right)}2(1−cos2x)2sinx=sin(x)1
limx→4(sin(3x)2x2cosx)\lim_{x\to4}\left(\frac{\sin\left(3x\right)^2}{x^2cosx}\right)x→4lim(x2cosxsin(3x)2)
f(x)=2x−2f ( x ) = 2 x - 2f(x)=2x−2
33⋅320033\cdot320033⋅3200
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