$\int\left(\frac{3x}{\sqrt{x^2+6}}\right)dx$
$3x^2-6x^3$
$\left(x^2-22x+125\right)$
$\int\frac{\left(4-\sqrt{x}\right)}{\left(4+\sqrt{x}\right)}dx$
$3x=9x$
$5x^2+4x-1$
$\left(3-x\right)\left(\frac{7}{x^2}-6\right)$
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