$\left(2x^3+8y^4\right)^2$
$\frac{\sec^2\left(u\right)-1}{\sec^2\left(u\right)}$
$15+\left(-6\right)^0-3^{-2}$
$\int\left(\frac{1}{\left(1-x\right)^3}\right)dx$
$3m^2+2mn+n-2mn$
$\left(1+x^8\right)^4$
$\lim_{x\to\infty}\left(\frac{x+3}{4}\right)$
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