8a2b−4b28a^2b-4b^28a2b−4b2
ddx(3y+2)3=7x3−3x\frac{d}{dx}\left(3y+2\right)^3=7x^3-3xdxd(3y+2)3=7x3−3x
(+x2+y2)−(−x2+y2)\left(+\sqrt{x^2+y^2}\right)-\left(-\sqrt{x^2+y^2}\right)(+x2+y2)−(−x2+y2)
(x+2a+y)2\left(x+2a+y\right)^2(x+2a+y)2
(2x2)4\left(\sqrt{2x^2}\right)^4(2x2)4
x2−5x−5x^2-5x-5x2−5x−5
(tan2(x−1))(tan2(x+1))⋅2cos2(x)\frac{\left(\tan^2\left(x-1\right)\right)}{\left(\tan^2\left(x+1\right)\right)}\cdot2\cos^2\left(x\right)(tan2(x+1))(tan2(x−1))⋅2cos2(x)
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