−5y − 5 = −20-5y\:-\:5\:=\:-20−5y−5=−20
5x=355x=355x=35
q9−83q^9-8^3q9−83
20(x2−16)5(x−1)(x+4)\frac{20\left(x^2-16\right)}{5\left(x-1\right)\left(x+4\right)}5(x−1)(x+4)20(x2−16)
limx→4(x3+8x+2)\lim_{x\to4}\left(\frac{x^3+8}{x+2}\right)x→4lim(x+2x3+8)
55m2n3x+110m2n3x2−220am2y355m^2n^3x+110m^2n^3x^2-220am^2y^355m2n3x+110m2n3x2−220am2y3
∫ x−1x3+3x2+2xdx\int\:\frac{x-1}{x^3+3x^2+2x}dx∫x3+3x2+2xx−1dx
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