$\left(3y-8\right)\left(y+3\right)$
$\lim_{x\to\infty\:}\left(\frac{\left(12-x\right)}{x^5}\right)$
$y'+3y''+2y=0$
$15x^3y^5-20x^5y^2$
$-\frac{2}{x^3-x^2}$
$\frac{x^3}{x^5}$
$16+2-8t+1$
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