$\int_{-2}^2\left(\frac{1}{x^2+4x+13}\right)dx$
$72y+43y+24x+32y+21x+12x$
$12^2\:x\:2\:+\:\:\frac{40}{5}\:-6^2\:+\:9$
$778\:+\:\left(-512\right)$
$\lim_{x\to4}\left(\frac{y^2-16}{\sqrt{y}-2}\right)$
$3x^2+2x-5=22$
$2x-1=3$
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