$-7x+15\le-5x+1$
$\lim_{x\to3.99}\left(\frac{x^2-16}{x+4}\right)$
$\left(2x^2y\right)\left(3x^4y^2\right)\left(-\frac{5}{18}xyz\right)$
$-4^6$
$-14x^2\:+\:12x\:+\:26$
$\lim_{x\to0}\left(\frac{e^x+3x-1}{5^x}\right)$
$x\left(7x+4\right)=0$
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