$7\cdot3+6$
$x^2-2x+17$
$\left(15x^{6}-70x^{5}+10x^{4}-5x^{3}\right)\left(-5x^{3}\right)$
$\lim_{x\to\infty}\frac{3x^3+4x^2-5}{2x^2-3x+6}$
$x^2-2x-63=0$
$2x^2-5x+1$
$2\:-3\:7$
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