$5\left(-9f-9\right)+7f$
$\int2f^{-5x}dx$
$\frac{ln\left(\frac{\left(3-x\right)}{2}\right)}{2\cdot\left(3-x\right)^3}$
$1\frac{1}{x}$
$\:\frac{tan\theta\:}{sec\theta\:\:}$
$7x-5<4x-11$
$x^2+4x=7x-8$
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