$64\left(1\right)^5$
$\frac{x^2-4x+4}{x^2-x-2}$
$\int\frac{5x^2+20x+6}{\left(x^2-x\right)\left(x^2+4\right)}dx$
$w=in\left(\frac{uv}{st}\right)$
$\left(-x^2-4\right)-\left(x^2+x\right)$
$30x^2+7x+15$
$\left(w^2+3w\right)\left(3w+6w^2\right)\:$
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