15<x−3x+1\frac{1}{5}<\frac{x-3}{x+1}51<x+1x−3
∫ x+1x3+x2−6x dx\int\:\frac{x+1}{x^3+x^2-6x}\:dx∫x3+x2−6xx+1dx
(2x)3⋅(2x)4\left(2x\right)^3\cdot\left(2x\right)^4(2x)3⋅(2x)4
dydx+3xy2=x\frac{dy}{dx}+3xy^2=xdxdy+3xy2=x
6−2, 48−1, 22636-2,\:48-1,\:22636−2,48−1,2263
(2x2−32x)3\left(2x^2-\frac{3}{2}x\right)^3(2x2−23x)3
(34x4+23y)(34x4+23y)\left(\frac{3}{4}x^4+\frac{2}{3}y\right)\left(\frac{3}{4}x^4+\frac{2}{3}y\right)(43x4+32y)(43x4+32y)
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