$x^3+10x^2-22x$
$\int\frac{\left(3y\right)}{\left(1+y^2\right)}dy$
$243=m^{\frac{5}{4}}$
$6xy-12x-7y+14$
$\frac{2x^5+6x^4+2x^2-33x+10}{x-4}$
$\left(-x^2\:+\:5\:x\right)\:-\:\left(6\:x^2\:+\:x\:-\:2\right)$
$\tan^2\left(36.87\right)$
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