$\int6^{3x^2}xdx$
$\frac{dp}{dt}=-4p$
$16x^2-y^2$
$tan^8\cdot sec^6$
$\frac{d^4y}{dx^4}+\frac{2d^2y}{dx^2}+y=0$
$x^2-x-12\ge0$
$\left(8b^2-7a\right)\left(2ab+2a^2\right)$
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