$\left(2a^2+4\right)\left(2a^2-4\right)$
$\left(4b-5\right)\left(4b+5\right)$
$15^1\cdot15^0$
$\frac{x^2}{y^2-8}\frac{dy}{dx}=\frac{1}{2y}$
$\int\left(\frac{\left(x^2\right)}{\sqrt{x^6+64}}\right)dx$
$2\sqrt{27x^2y^5}$
$\lim_{x\to2}\:\frac{x^2+3x+2}{x^2-5x+6}$
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