$-3x^2+2x-5$
$-2+4+3+4$
$\frac{1}{7}-3\left(\frac{3}{7}m-\frac{2}{7}\right)$
$\lim_{x\to\infty}\left(\frac{\left(-2x^2+3x-1\right)}{5-2x^2}\right)$
$5\left(5x+4y\right)\:\:\:\:5\left(5x-4y\right)$
$5.368+15+0.53$
$\left(9-2n\right)^2$
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