$\int\frac{16x^2}{\left(x-18\right)\left(x+6\right)^2}dx$

$8y^2+64y+1024$

$\frac{\sin^2\left(a\right)}{\cos\left(a\right)}+\cos\left(a\right)$

$4\left(v+5\right)-8v$

$\frac{\sin^2}{\cos^2x}=\sec^2x-1$

$6\cdot\left(-6\right)+3$

$\lim_{x\to\infty}\left(\frac{x^2+1}{3^x}\right)$