$c\:-\:15c\:-\:10\:+\:12c\:-\:8$
$\left(x^{-3}.z^4\right)^5$
$\left(2x+4y^5\right)^3$
$\left(-2x^2y^3z^3\right)^4\left(3xz^4\right)$
$\left(x^2+1\right)\cdot\left(x-1\right)$
$\frac{2x^3+4x^2-6x}{x+3}$
$-7+\left(-5\right)-\left(-12\right)$
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