$1+-1+2+-2+3$
$q^2-48q+24$
$+6-3+2$
$1+\frac{1}{x}>=0$
$x^2+6x+8\ge0$
$\left(x^2-1\right)\left(x^2+x\right)$
$\lim_{x\to\infty}\left(-3x^2-2x-5\right)$
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