$\frac{3abc}{m^{-5}}$
$\frac{d^2}{dx^2}\frac{\left(x^2+4x+4\right)}{\left(x-3\right)}$
$\int\frac{x-6}{2}dx$
$\left(x+1\right)\left(x-3\right)\left(z-1\right)$
$15+\left(3-\left(-11-\left(13+\right)-7\right)\right)$
$\:6senx+3=1$
$\lim_{x\to4}\:\sqrt{\frac{x^2-2x+3\:}{3x+4}}$
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