$10x-9>3x+5$
$\sqrt{\frac{5}{6.7^3}}$
$y\cdot\frac{dx}{dy}=2xe^{y^2}$
$\left(3x+9\right)\left(3x+2\right)$
$14.29+10.43+5.42$
$\frac{dy}{dx}\sqrt{x}=\sqrt{x}+1$
$\left(2x^3+5y^2\right)^2$
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