$\frac{1}{\left(x^2+x\right)}dx=\frac{1}{\left(y-1\right)}dy$

$\left(\frac{sin^2\left(x\right)}{1+cos\left(x\right)}\right)=1-cos\left(x\right)$

$\frac{10q^5w^7}{2w^3}\cdot\frac{4\left(q^6\right)^2}{w^{-5}}$

$\left(x-3\right)\left(5-x\right)$

$4x\:+\:8y\:=\:2\left(2x\:+\:4y\right)$

$\int\left(18x^2\ln\left(x+1\right)\right)dx$

$\frac{\left(x+2\right)^2}{2x-1}$